Philosophy 112
Overview
Section 2.6 introduces a method for abbreviating derivations. The software calls it “queuing.” Section 2.7 discusses some theorems. Section 2.8 introduces derived rules.
Queuing
Here is the idea. Consider the following derivation:
P ∧ Q . P → R ∴ R
1ShowR
2P ∧ Qpr
3P2 s
4P → Rpr
5R4 5 mp
65 dd
We have already seen two ways in which this can be shortened: we can use the premises directly instead of bringing them down; we can apply ‘dd’ to the end of line (5) instead of entering it on a separate line:
1ShowR
2Ppr1 s
3R2 pr2 mp dd
Let’s pause and consider both of these shortcuts.
Line (2) combines two steps into one:
- bring down PR2 (to get P ∧ Q)
- to the result above, apply S (to get P)
Line (3) also combines two steps into one:
- to line (2) and the result of bringing down PR2, apply MP (to get R)
- given that result, box and cancel by DD
You can combine steps like this on any line. So, for example,
1ShowR
2Rpr1 sl pr2 mp dd
To unpack this, work from left to right:
- bring down PR1
- to the result, apply SL (to get P);
- to the result (P) and PR2, apply MP (to get R)
- given that result (R), box and cancel by DD
Here is a second example.
P ∨ Q . ∼ Q ∧ R∴ P
1ShowP
2P ∨ Qpr
3 ∼ Q ∧ Rpr
4P3 sl 2 mtp
5dd
On line (4), we have combined a two steps into one line:
- to (3), apply SL (to get ∼ Q)
- to the result and line (2), apply MTP (to get P)
We could compress the derivation yet further, if we wished, e.g.,
1ShowP
2Ppr2 sl pr1 mtp dd
Queuing makes derivations more difficult to read. I recommend using it judiciously if you feel quite confident in your ability to construct derivations. Otherwise, I don’t recommend using it at all.
Theorems and Derived Rules
Consider the theorem 24 (T24 in the software and the book, problem 2.024 in the software):
P ∧ Q ↔ Q ∧ P
This theorem tells us that the order in which conjuncts occur does not matter to the truth of a conjunction. Note that the same would not be true if we replaced the ∧’s with →’s.
Here is a derivation of the theorem:
1ShowP ∧ Q ↔ Q ∧ P
2ShowP ∧ Q → Q ∧ P
3P ∧ Qass cd
4P3 sl
5Q3 sr
6Q ∧ P4 5 adj cd
7ShowQ ∧ P → P ∧ Q
8Q ∧ Pass cd
9Q8 sl
10P8 sl
11P ∧ Q9 10 adj cd
12P ∧ Q ↔ Q ∧ P2 7 cb dd